[Scons-users] Source paths across external projects
Bobby Casey
beecee808 at gmail.com
Fri Sep 9 11:46:24 EDT 2016
Wow, I feel awfully foolish right now. The first suggestion ( `src =
[File("src/foo.c")]' ) is a perfect solution.
For some reason it didn't occur to me that File would preserve the file
path based upon the file loaded, unlike when using strings.
Thanks for the help!
On Thu, Sep 8, 2016 at 9:27 PM Bill Deegan <bill at baddogconsulting.com>
wrote:
> Bobby,
>
> How about:
>
> In the example above, `top_project/SConscript' would look like this:
> src = SConscript('sources.scons')
> foo =SConscript('extern/foo/sources.scons')
> src.extend(foo)
> prog = Program('test', src)
>
> and `extern/foo/sources.scons' would look like this:
> src = [File('src/foo.c')]
> Return('src')
>
> Or:
> src = [SharedObject('src/foo.c')]
> Return('src')
>
>
>
> On Thu, Sep 8, 2016 at 11:15 AM, Bobby Casey <beecee808 at gmail.com> wrote:
>
>> Hello,
>>
>> I'm going to start by apologizing for the length of this email. I
>> started off trying to explain what I'm looking for and what I have done and
>> ended up trying other ideas as I went along.
>>
>> So here's what I'm trying to do - I have a project that depends on
>> several external source repositories. The structure looks something like
>> this:
>>
>> top_project/
>> ---> SConstruct
>> ---> SConscript
>> ---> sources.scons
>> ---> extern/foo
>> ------> SConstruct
>> ------> SConscript
>> ------> sources.scons
>> ------> src/
>> ---------> foo.c
>> ---> extern/bar
>> ......
>>
>> Where each of the "extern" projects (there are several) is a separate
>> repository that is capable of building itself (generally for testing
>> purposes) and contains a sources.scons file that top_project's SConscript
>> file pulls in to grab the list of source files that the sub-project
>> provides. The problem, however, is that when `top_project/SConscript' calls
>> `SConscript("extern/foo/sources.scons")', all the paths are relative to
>> top_project (rather than extern/foo).
>>
>> This is a bit hard to explain, let me give a visual.
>>
>> In the example above, `top_project/SConscript' would look like this:
>> src = SConscript('sources.scons')
>> foo =SConscript('extern/foo/sources.scons')
>> src.extend(foo)
>> prog = Program('test', src)
>>
>> and `extern/foo/sources.scons' would look like this:
>> src = ['src/foo.c']
>> Return('src')
>>
>> This will fail with the following error:
>> scons: *** [build/src/foo.o] Source `build/src/foo.c' not found,
>> needed by target `build/src/foo.o'.
>>
>> That is, of course, the correct behavior - just not the behavior what I
>> wanted! I could prepend os.path.abspath before each file, but that leaves
>> the object files next to the sources, ignoring any variant_dir that was
>> specified in top_project/SConstruct.
>>
>> I worked around this by modifying top_project/SConscript to look like
>> this instead:
>> def add_scons_source(proj_dir):
>> src = SConscript('%s/sources.scons' % proj_dir)
>> src = ['%s/%s' % (proj_dir, s) for s in src]
>> return src
>>
>> src = SConscript('sources.scons')
>> src.extend( add_scons_source('extern/foo') )
>> prog = Program('test', src)
>>
>> This prepends the appropriate path to each source file and works just
>> fine but feels decidedly "unsconsy". I then considered having each
>> sources.scons be responsible for building it's own object files and that
>> works great. It's exactly what I wanted for building the application. I
>> suspect this is also the canonically correct way to do it. The problem is
>> that, in our real application, we also have a lint target that needs to be
>> run against all source files so that it can detect issues across
>> compilation units. I'd like to avoid having the external projects know
>> anything about lint, or whatever other targets are available in the
>> top_project, so I came up with this as a possible solution.
>>
>> top_project/SConscript would look something like this:
>> env = Environment()
>> source_list = []
>> def do_lint(target, source, env):
>> print 'running lint on %s' % (str(s) for s in source)
>>
>> def aggregate_sources(target, source, env):
>> global source_list
>> source_list.extend( [str(s) for s in source] )
>>
>> env.Append(BUILDERS={'AggregateSources':
>> Builder(action=aggregate_sources)})
>> env.Append(BUILDERS={'LintBuilder': Builder(action=do_lint)})
>>
>> SrcBuilder = env.Object
>> src = SConscript('sources.scons', exports=['SrcBuilder'])
>> src.extend( SConscript('extern/foo/sources.scons',
>> exports=['SrcBuilder']) )
>>
>> prog = env.Program('test', src)
>> Default(prog)
>>
>> SrcBuilder = env.AggregateSources
>> lint_src = SConscript('sources.scons', exports=['SrcBuilder'])
>> lint_src.extend( SConscript('extern/foo/sources.scons',
>> exports=['SrcBuilder']) )
>> lint = env.LintBuilder('lint.out', lint_src)
>>
>> Alias('lint', lint)
>>
>> and the sources.scons files would all look something like this:
>>
>> Import('SrcBuilder')
>> src = ['src/foo.c']
>> built = [SrcBuilder(s) for s in src]
>> Return('built')
>>
>> This looks a bit silly in this contrived example because the SrcBuilder
>> would really be part of two separate environments (one for Program and one
>> for Lint targets), but I think you get the point. The advantage to this
>> method is that the builder is provided to sources.scons so it need not know
>> how we're using the sources but can still handle them appropriately. The
>> disadvantage is that SrcBuilder needs to either be some common name for two
>> wildly different things that are either part of the environment or passed
>> as an extern. It would be nicer if I could say something like `export(
>> env.Object as "SrcBuilder")' and `export( env.AggregateSources as
>> "SrcBuilder")'. Is there some way to do this?
>>
>> I would appreciate any comments/feedback/suggestions/criticism. Are any
>> of these methods even remotely sound? Is there some canonical way of doing
>> this that I have just totally missed somehow? Am I proposing a flawed
>> architecture that could be easier/better done in some other way?
>>
>> Thanks in advance,
>> Bobby
>>
>>
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>>
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