[Scons-users] Getting directory in which Sconscript is running

[William Blevins]

I'm still not 100% clear.  A mock directory structure would be nice.

My interpretation.  You need to call a script from an SConscript but dont
want to hardcode the module location?  Put the script into '#site_scons'.
These get added to the python path automatically.

My other interpretation. The X location isnt fixed and needs to be
configurable.  Add an argument to your sconstruct so the caller can
configure locally.  (EG.  Scons --xpath=<path> and they can add the
argument to an alias)

I hope that helps.  If nether interpretation makes sense then I can only
assume you are trying to autogen paths magically without a good problem
description.

V/R,
William

On May 1, 2014 12:33 PM, "Tom Tanner (BLOOMBERG/ LONDON)" <
ttanner2 at bloomberg.net> wrote:

>

> I need to run a python script which needs a python path specified. The

python modules are in a subdirectory of where the sconscript is running.

>

> so this'd involve

>

> PYTHONPATH=<path-to-repo>/A/B $SOURCES $TARGETS

>

> as the source is a repository (which might live in different locations

for different users) all the paths are absolute, so I thought it'd be
easier to pass them in by setting env['ENV']['PYTHONPATH'] rather than
putting PYTHONPATH=$(path to repo$}/A/B in the command. I might be wrong.

>

> ----- Original Message -----

> From: bill at baddogconsulting.com

> To: Tom Tanner (BLOOMBERG/ LONDON), scons-users at scons.org

> At: May 1 2014 17:25:39

>>

>> Tom,

>>

>> Not sure what you're really trying to do, but it sounds ugly.

>> I've found if it's hard to do, you're probably doing it wrong..

>>

>> Perhaps you can expand on the what you're trying to do, rather than the

'how you're trying to do it'..

>>

>> -Bill

>>

>>

>> On Thu, May 1, 2014 at 9:23 AM, Tom Tanner (BLOOMBERG/ LONDON) <

ttanner2 at bloomberg.net> wrote:

>>>

>>> I've found half the answer. Dir('.').path gives me A/B

>>>

>>> Now I need to find the path of the actual directory that contains the

SConscript (I know I can do os.path.dirname(File('SConscript').rstr()) but
- that is not pretty)

>>>

>>>

>>> ----- Original Message -----

>>> From: ttanner2 at bloomberg.net

>>> To: scons-users at scons.org

>>> At: May 1 2014 17:19:59

>>>>

>>>> But I don't want to do #A/B. What happens if for some reason, I want

to move B (or A). Or want to share code between 2 SConscripts.

>>>>

>>>> ----- Original Message -----

>>>> From: wblevins001 at gmail.com

>>>> To: Tom Tanner (BLOOMBERG/ LONDON), scons-users at scons.org

>>>> At: May 1 2014 17:00:00

>>>>>

>>>>> See scons 2.3.1 user guide 14.3 for more.

>>>>>

>>>>> On May 1, 2014 11:55 AM, "William Blevins" <wblevins001 at gmail.com>

wrote:

>>>>>>

>>>>>> The '#' symbol always refers to the SConstruct dir, so you can refer

as '#A' join 'B' and files stay relative to the root src dir.

>>>>>>

>>>>>> V/R,

>>>>>> William

>>>>>>

>>>>>> On May 1, 2014 11:48 AM, "Tom Tanner (BLOOMBERG/ LONDON)" <

ttanner2 at bloomberg.net> wrote:

>>>>>>>

>>>>>>> I'd really like to be able to get hold of the current SConscript

directory relative to the SConstruct path, so with a directory structure in
a repository a little like this:

>>>>>>>

>>>>>>> +-SConstruct

>>>>>>> |

>>>>>>> +-A

>>>>>>> |

>>>>>>> +-B

>>>>>>> |

>>>>>>> +-SConscript

>>>>>>>

>>>>>>> There will be something I can do in the SConscript that will get me

"A/B" (i.e. the relative directory in which things will be built), and
<wherever the source is>/A/B, which is the sort of thing I need to stuff in
environment variable (for instance for getting the right PYTHONPATH for
running python scripts which live in a subdirectory of B).

>>>>>>>

>>>>>>> Using Dir('.').rstr() or .rdir() will get you '.'. Throwing

srcdir().abspath into the mix will get me the full path to the build
directory, not the full path to the source directory.

>>>>>>>

>>>>>>>

>>>>>>>

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>>>>>>>

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>>>>>>>

>>>>

>>>>

>>>>

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>>>

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>>

>

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