[Scons-users] Getting directory in which Sconscript is running

[Bill Deegan]

Tom,

Stick the information in a shared Environment()

env['MY_A_LIB_INFO'='...'

And/or put the shared logic in your scons_info dir under you SConstruct.

-Bill


On Thu, May 1, 2014 at 9:11 AM, Tom Tanner (BLOOMBERG/ LONDON) <
ttanner2 at bloomberg.net> wrote:


> But I don't want to do #A/B. What happens if for some reason, I want to

> move B (or A). Or want to share code between 2 SConscripts.

>

>

> ----- Original Message -----

> From: wblevins001 at gmail.com

> To: Tom Tanner (BLOOMBERG/ LONDON) <ttanner2 at bloomberg.net>,

> scons-users at scons.org

> At: May 1 2014 17:00:00

>

> See scons 2.3.1 user guide 14.3 for more.

> On May 1, 2014 11:55 AM, "William Blevins" <wblevins001 at gmail.com> wrote:

>

>> The '#' symbol always refers to the SConstruct dir, so you can refer as

>> '#A' join 'B' and files stay relative to the root src dir.

>>

>> V/R,

>> William

>> On May 1, 2014 11:48 AM, "Tom Tanner (BLOOMBERG/ LONDON)" <

>> ttanner2 at bloomberg.net> wrote:

>>

>>> I'd really like to be able to get hold of the current SConscript

>>> directory relative to the SConstruct path, so with a directory structure in

>>> a repository a little like this:

>>>

>>> +-SConstruct

>>> |

>>> +-A

>>> |

>>> +-B

>>> |

>>> +-SConscript

>>>

>>> There will be something I can do in the SConscript that will get me

>>> "A/B" (i.e. the relative directory in which things will be built), and

>>> <wherever the source is>/A/B, which is the sort of thing I need to stuff in

>>> environment variable (for instance for getting the right PYTHONPATH for

>>> running python scripts which live in a subdirectory of B).

>>>

>>> Using Dir('.').rstr() or .rdir() will get you '.'. Throwing

>>> srcdir().abspath into the mix will get me the full path to the build

>>> directory, not the full path to the source directory.

>>>

>>>

>>>

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>>>

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>

>

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