[Scons-users] Getting directory in which Sconscript is running

[William Blevins]

The '#' symbol always refers to the SConstruct dir, so you can refer as
'#A' join 'B' and files stay relative to the root src dir.

V/R,
William
On May 1, 2014 11:48 AM, "Tom Tanner (BLOOMBERG/ LONDON)" <
ttanner2 at bloomberg.net> wrote:


> I'd really like to be able to get hold of the current SConscript directory

> relative to the SConstruct path, so with a directory structure in a

> repository a little like this:

>

> +-SConstruct

> |

> +-A

> |

> +-B

> |

> +-SConscript

>

> There will be something I can do in the SConscript that will get me "A/B"

> (i.e. the relative directory in which things will be built), and <wherever

> the source is>/A/B, which is the sort of thing I need to stuff in

> environment variable (for instance for getting the right PYTHONPATH for

> running python scripts which live in a subdirectory of B).

>

> Using Dir('.').rstr() or .rdir() will get you '.'. Throwing

> srcdir().abspath into the mix will get me the full path to the build

> directory, not the full path to the source directory.

>

>

>

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