[kj] OT: The origins of goth?

Phillipps, Marc Marc.Phillipps at nclondon.nhs.uk
Thu Nov 22 11:00:52 EST 2012


I'd say Bauhaus were the first band who could be truly called "goth"



. . . Banshees were influential but were really a punk band . . UK
Decay? Sex Gang Children? A lot of those bands around 80/81/82 were
toying with the imagery I guess?







From: gathering-bounces at misera.net [mailto:gathering-bounces at misera.net]
On Behalf Of Per G Olsson
Sent: 22 November 2012 13:18
To: A list about all things Killing Joke (the band!)
Subject: Re: [kj] OT: The origins of goth?



Yep, I know that the term is extremely widely used.

Sticking my neck out as little as possible I'd say that
Sisters of Mercy and Bauhaus fully fits my expectations of "goth".

Also early Specimen, a bit of Joy Division, early Clan of
Xymox etc etc...





22 nov 2012 kl. 14.07 skrev wessidetempest .:





I guess it depends on what you consider goth. For example there are
metal bands that are considered. And from my opinion it's only because
they dress the part.

On Nov 22, 2012, at 8:02 AM, "Per G Olsson"
<Per.G.Olsson at Miljonmysteriet.com> wrote:

As the list pretty quiet at the moment (strange
considering that Jaz & Youth apparently are releasing stuff and and a KJ
single is supposedly due soon) I'd thought I ask a "simple" question...



Anyone out there who has a good idea on tracking the
roots of "goth"?



As with the term "punk" there are many different
views on what bands to include, but I hope that among KJ fans there are
quite a few that also listens to a lot of "goth".



The reason I ask is that I stumbled on this track by
The Glass Family from 1968 (http://youtu.be/q_pIiQUIZoA), which in my
ears sounds quite "gothic".

The rest of what The Glass Family released has very
little resemblance to "goth" (in my humble ears) so it seems to be a one
off.

Never heard any other 60:s track that sounds so
"gothic", but please feel free to enlighten me if there are others!





/Per





(Cue "It started in the UX" "No, it began in the
UY", where X and Y equals K or S depending on who starts)





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